Reflection of Video

As the agent of change, we have to learn more and more. We know that study not only transfer of knowledge from the teacher to the students, but also can be done in the other ways. A film / a video can be learning alternative media. Students have to analyze and then reflect in their daily lifes. There are some videos that I’ve seen.

Ø Video I

This film talking about how the teacher motivate his students. The teacher tell themabout W. Shakespeare, someone who write an interesting story. He talk very exciting and takes the students attention.

He jump on the table. He said that we don’t have to be afraid to make some mistakes. We must try to find our own voice. We must begin and find new ground. We must break out! We must look at something in different way. In the last part, his action has done by his students.

Ø Video II

This video grounded at the stage round by a lot of audiens. The host let a little boys to raise on the stage. The children ask the audiens whether they believe at him again and again. He said that he do anything, because anything, cause they believe at him. He is very confident.

Ø Video III

It is an exciting video. This scene offered in a rap music by two college students. It’s shows the high spirits of mathematicians. “What you know about math?” This question is given for us. What we know about math? A significant figure, limit, trigonometry, math B, curves, exponent to decline, integral, square and cubic equation, plus, minus, multiplycation, and overing (+ - x ¸).

“What you know about math?” I know all about math….

Ø Video IV

This video shows how to solve the differential equation.

First, we must find y =f (x), satisfies the equation for values x & y.

Dy = 4x dx, integrate

, try to get dependent variable y all by itself

dy = 4x² dx , integrate the whole equation, integrate

, represent the infinite family of solution curve

, infinite of identical curve

Ø Video V

There are some problem study in a linear equation.

1) X-5=3

To solve this problem, first step is makes one part become 0 by adding the left part and the right one with -3. So, the pattern being X-5-3=3-3. This form more simple in X-8=0. So, the value of X=8.

2) 7=4a-1

First we must add both of parts by 1, and the pattern is 7+1=4a-1+1. The simple pattern: 8=4a. The right part is multiplication, so the next step is over 8 by 4 or multiply both of the part by ¹/₄, and we get the value of a=2.

3) ²/₃X=8

First, we have to change the part with the x variable has the coefficient of 1 by multiply both of the parts with ³/₂. So, x=8׳/₂ , and we get the value of X=12.

4) 5-2x=3x+1

Add both of the part by -3x. The form being 5-5x=1

Add both of the part by -5, so the pattern become -5x=-4

Thew next step is multiply both of the part by -¹/_5.

-¹/₅ (-5x)= -¹/₅ (-4), so we get that x=⁴/₅.

5) 3-5(2m-5)=-2

For this problem, use the same rules with the problems before. Combines the number in front of the bracket.

3-10m+25=-2, use the same rules and we get 30=10m. So, m=3. The problem is solved.

Ø Video VI

This video show how to find the logarithm pattern by the simple pattern before. We know that log_xA=B is equal to x^B=A. And C(log_xA)=B×C is equal to x^BC=A^C , so log_x(A^C)=BC.

We also know that C×log_xA=log_xA^C and log_xA+log_xB=log_xA×B

So, if log_xA=l => x^l = A

log_x B=m => x^m=B

and log_x A/B=n => xⁿ =A/B = x^l/xⁿ = x^l-n

and we get the new logfarithm is log_xA/B= log_xA-log_xB